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Isotopes not close enough to the Valley of stability are not stable, as they have too little or too many neutrons. All their possible stable isotope candidates are already taken by their neighbors as energetically preferred variants.
Therefore all isotopes of given 2 elements beta decay to nuclei of adjacent elements with less energy. Sign up to join this community. The best answers are voted up and rise to the top. Stack Overflow for Teams — Collaborate and share knowledge with a private group. Create a free Team What is Teams? Learn more. Why is Promethium the only radioactive Lanthanide? Ask Question. Asked 5 years, 2 months ago. Active 1 year, 7 months ago. Viewed 6k times. Improve this question. Promethium being radioactive is just bad luck.
Technetium is another such case. The issue isn't f-electrons so much as nuclear structure, where it turns out that the Samarium nucleus is more tightly bound see nuclear shell model , so flipping one of Promethium's neutrons to a proton results in a lower-energy nucleus not that it stops there in general, but It is the only one with no stable isotopes. Other stable lanthanides also have naturally occurring radioactive isotopes samarium is a good example.
It is well-established that nuclear properties can affect chemical properties. Granted, it's not typical, but it's nevertheless incorrect to take the hard-line stance that it doesn't happen at all. See, for instance: tandfonline. If we start with exceptions, the students never get to know the rules in the first place. Here I stand, and I can do no other. Show 1 more comment.
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